The length and the width of the rectangle are 22 inches and 16 inches respectively
<h3>How to determine the length and the width of the rectangle?</h3>
The given parameters are:
Length = 6 inches + width
Perimeter = 76 inches
The perimeter is calculated as:
Perimeter = 2 * (Length + Width)
This gives
76 inches = 2 * (6 inches + Width + Width)
Divide through by 2
38 inches = 6 inches + Width + Width
Evaluate the like terms
2 * Width = 32 inches
Divide both sides by 2
Width = 16 inches
Substitute Width = 16 inches in Length = 6 inches + width
Length = 6 inches + 16 inches
Evaluate
Length = 22 inches
Hence, the length and the width of the rectangle are 22 inches and 16 inches respectively
Read more about perimeters at:
brainly.com/question/24571594
#SPJ1
The answer is B. 2m/5
60 nails cost m dollars
60nails = m dollars
so 1 nail = m / 60
so for 24 (m/60) * 24 = 2m/5
Check the picture below.
the segment LOJ is a diameter, and therefore the arcLCJ made by that diameter will have a central angle of 180°.
that simply means that the arcLC is 180 - 94, or 86°.
the ∡LJC is an inscribed angle that is intercepting the arcLC, and therefore, by the inscribed angle theorem, it'll be half of arcLC.
The answer is (-2,0) (2,0) (0,-4)
Answer:
C
Step-by-step explanation:
If
then

Substitute them into the equation 

Given
then

Hence,
