Answer:
Step-by-step explanation:
From the given information,
Suppose
X represents the Desktop computer
Y represents the DVD Player
Z represents the Two Cars
Given that:
n(X)=275
n(Y)=455
n(Z)=405
n(XUY)=145
n(YUZ)=195
n(XUZ)=110
n((XUYUZ))=265
n(X ∩ Y ∩ Z) = 1000-265
n(X ∩ Y ∩ Z) = 735
n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)
145 = 275+455 - n(X ∩ Y)
n(X ∩ Y) = 585
n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)
195 = 455+405-n(Y ∩ Z)
n(Y ∩ Z) = 665
n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)
110 = 275+405-n(X ∩ Z)
n(X ∩ Z) = 570
a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)
n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735
n(X ∪ Y ∪ Z) = 50
c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)
n(X ∪ Y ∪ C') = 145-50
n(X ∪ Y ∪ C') = 95
For the table, y = 25x.
When x = 12, y = 25*12 = 300
For the graph, y = 30x
When x = 12, y = 30*12 = 360
When x = 12, the value of y on the graph is 60 more than its value in the table.
Answer + Step-by-step explanation:
1) The probability of getting 2 white balls is equal to:
2) the probability of getting 2 white balls is equal to:
3) The probability of getting at least 72 white balls is:
![=\sum^{150}_{k=72} [C^{k}_{150}\times \left( \frac{8}{15} \right)^{k} \times \left( \frac{7}{15} \right)^{150-k}]](https://tex.z-dn.net/?f=%3D%5Csum%5E%7B150%7D_%7Bk%3D72%7D%20%5BC%5E%7Bk%7D_%7B150%7D%5Ctimes%20%20%5Cleft%28%20%5Cfrac%7B8%7D%7B15%7D%20%5Cright%29%5E%7Bk%7D%20%20%5Ctimes%20%5Cleft%28%20%5Cfrac%7B7%7D%7B15%7D%20%5Cright%29%5E%7B150-k%7D%5D)
Answer:
1/4
Step-by-step explanation:
If there are 4 gold coins, and 1 silver coin, there is 1 silver coin to 4 gold coins. This results in 1 to 4 , 1/4.
