Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
Dude that’s not an answer
Answer:
2 ≤ x < 7
Step-by-step explanation:
-1 ≤ x – 3 < 4
Add 3 to each side
-1+3 ≤ x – 3+3 < 4+3
2 ≤ x < 7
" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google
Answer and Step-by-step explanation:
We know that t is in minutes, and 1 hours is equal to 60 minutes, so we plug in 60 for t.
C = 0.25(60) + 3.50
C = 15 + 3.50
C = 18.50
<em><u>The cost to rent the canoe is $18.50.</u></em>
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<em><u>#teamtrees #PAW (Plant And Water)</u></em>
