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ExtremeBDS [4]
3 years ago
13

Find the area of the polygon:

Mathematics
1 answer:
Darya [45]3 years ago
8 0

Answer:

Step-by-step explanation:

o find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

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Which of the following correctly graphs the system of equations?<br><br> {y=x−3<br> y=−2x+3
8_murik_8 [283]

The third one

This graph is the only one that shows the correct slops with the correct y intercepts (-3 and 3)

4 0
3 years ago
The length, in centimeters, of a diagonal of a rectangle is represented by the expression below.
TiliK225 [7]

Answer:

(C) 18 centimeters

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2 years ago
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Simplify: 64 ∙ 42 − 3 ∙ 22
ollegr [7]

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59070

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
Suppose you roll a cube 30 times, what is a to describe the theoretical of rolling a 1, 4, 6, 7 Please help me!
Free_Kalibri [48]

Answer:

Pr(x) = \frac{1}{6}

Step-by-step explanation:

Given

n = 30 --- number of rolls

Required

The theoretical probability of rolling: (a) 1    (b) 4    (c) 6    (d) 7

Assume the cube is 6 sided.

The sample space is:

S = \{1,2,3,4,5,6\}

And the probability of each is:

Pr(x) = \frac{1}{6}

Irrespective of the number of rolls, the theoretical probability of (a). (b), (c) and (d) is:

Pr(x) = \frac{1}{6}

7 0
3 years ago
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