Answer:
15.3feet
Step-by-step explanation:
Given the scale model of a train as;
2cm = 3feet
We are to find the height of real train of height 10.2cm, we can write;
10.2cm = x
Divide both expressions
2/10.2 = 3/x
2x = 3×10.2
2x = 30.6
x= 15.3
Hence the height if the real train is 15.3feet
Trapezoid and isocseles trapezoid
Given the following question:
First expression:
Second expression:
Answer:
If we look at ΔBDH, we notice that m∠BHG has to be 108 - 36 - 39 = 105°. Because x and ∠BHG are a linear pair we know that x = 180 - ∠BHG = 180 - 105 = 75°.
The answer should be; 729 cm^3
