Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
Answer:
https://www.biology-pages.info/T/Tropisms.html
Explanation:
This link holds all the information you need :D
Hi
The answer is called a mutation
Answer:
Cells do not repair damage to DNA during mitosis because telomeres could fuse together. ... Throughout a cell's life, corrective mechanisms act to repair DNA strand breaks. The exception is during the critical moment of cell division, when chromosomes are most vulnerable.
Explanation:
The answer is C. heliobactir Pylori