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4 years ago

Name the quadrilateral with exactly one pair of parallel sides?

Mathematics

2 answers:

Zina [86]4 years ago

8 0

B. parallelogram

hope this helps<3

alina1380 [7]4 years ago

8 0

The correct answer to your question is B. Parallelogram.

Reasoning:
A parallelogram is a simple quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.

I hope this helps!
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Please show me the step on how to do this. I know the answer but how do you get it.

kozerog [31]

So, to find the volume of just the cement part, you need to find the volume of the whole shape, then find the volume of the garden. then subtract them to find the volume of just the cement sidewalk.

volume of garden: 16 x 6 x 1 (l x w x h)= 96 ft3

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4 years ago

Translate each verbal expression into an algebraic expression. Then simplify the expression.

mylen [45]

Answer:

6x x 9= 54x

Step-by-step explanation:

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3 years ago

You may remember that the area of a triangle is A=12B⋅H, where B is the base of the triangle and H is the height.

Alexxandr [17]

Answer:

b = 6

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

9 = 1/2 *(2h) * h

9 = h^2

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3 =h

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b = 2(3)

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4 years ago

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An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

Step-by-step explanation:

Let's denote the events as follows:

F = The word free occurs in an email

S = The email is spam

V = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

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Semenov [28]

Answer:

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Step-by-step explanation:

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3 years ago

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