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3 years ago

HELPPPPPP MEEE PLEASEEEE

Mathematics

2 answers:

NikAS [45]3 years ago

4 0

140 I believe because you subtract 40 from 180 since the two angles equal 180

gladu [14]3 years ago

4 0

<h3>Answer: 140 degrees</h3>

Explanation:

Angle 4 = angle 1 (vertical angles)

angle 1 = angle 2 (alternate interior angles)

angle 4 = angle 2 (transitive property)

angle 4 = 40

angle 2 = 40

angle2+angle3 = 180 (linear pair)

angle3 = 180-angle2 = 180-40 = 140

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A quicker method is to use the same side exterior angle theorem which says that the same side exterior angles are supplementary (meaning the angles add to 180 degrees). So angle4+angle3 = 180 leads to angle3 = 140.

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Parker and Company pays Selma Stokes on a variable commission scale. In a month when Selma had net sales of $155,000, what was h

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Answer:

$9275

Step-by-step explanation:

Selma earns 5% on the first $40,000, which is $2000.

She earns 5.5% on the next $35,000, which is $1925.

She earns 6% on the next $25,000, which is $1500.

And she earns 7% on the last $55,000 (the amount over 100,000), which is $3850.

Altogether, Selma's commission is ...

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3 years ago

Find the constant of variation for the quadratic variation. 6y=4x^2

AlladinOne [14]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
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6y=4x^2\implies y=\cfrac{4x^2}{6}\implies y=\cfrac{2x^2}{3}\implies y=\stackrel{k}{\cfrac{2}{3}}x^2$

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3 years ago

1. Write and solve an expression

nata0808 [166]

Answer:

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Step-by-step explanation:

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4 years ago

The probability is 51% that the sample mean will be between what two values, symmetrically distributed around the population

Alisiya [41]

Answer:

The lower bound is, $-z=-0.69$ and the upper bound is $z=0.69$ .

Step-by-step explanation:

Let the random variable X follows a normal distribution with mean μ and standard deviation σ.

The the random variable Z, defined as $Z=\frac{X-\mu}{\sigma}$ is standardized random variable also known as a standard normal random variable. The random variable $Z\sim N(0, 1)$ .

The standard normal random variable has a symmetric distribution.

It is provided that $P(-z\leq Z\leq z)=0.51$ .

Determine the upper and lower bound as follows:

$P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755$

Use a standard normal table to determine the value of z.

The value of z such that P (Z ≤ z) = 0.755 is 0.69.

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3 years ago

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Mandarinka [93]

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