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valentinak56 [21]
3 years ago
5

Find the constant of variation for the quadratic variation. 6y=4x^2

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
6y=4x^2\implies y=\cfrac{4x^2}{6}\implies y=\cfrac{2x^2}{3}\implies y=\stackrel{k}{\cfrac{2}{3}}x^2
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Answer:

-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)

Step-by-step explanation:

The standard form of a linear equation is ax+by=c, where a , b, and c are constants in the equation.

Based on the equation you have provided, the standard form would be -3x+4y=12, where a=-3, b=4, c=12.

To find the y-intercept, set x=0.

-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3

Therefore, the y-intercept is (0,3).

Do the same thing for the x-intercept, but this time with y=0.

-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4

Therefore, the x-intercept is (-4,0).

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3 years ago
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2 years ago
You earn a weekly salary of $475 plus a 5.5% commission on sales at a gift shop. How much would you earn in a week if you sold $
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Then the rates of change are related by ...

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4 years ago
How to expand 2/3(12x-9)?
morpeh [17]

Distribute easy: 8x; 2/3 of 12 is 8.
8x-6

8x-6
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