Answer:
your answer is proably 15 i dont really know
Step-by-step explanation:
Answer:
Distributive
Step-by-step explanation:
Answer:
C would be the correct answer. :D
Answer:
0.599 is the probability that a randomly selected page does not need to be retyped.
Step-by-step explanation:
We are given the following in the question:
The number of typing errors made by a typist has a Poisson distribution.
![\lambda =7](https://tex.z-dn.net/?f=%5Clambda%20%20%3D7)
The probability is given by:
We have to find the probability that a randomly selected page does not need to be retyped
P(less than or equal to 7 mistakes in a page)
![P( x \leq 7) = P(x =1) + P(x=1) +...+ P(x=6) + P(x = 7)\\\\= \displaystyle\frac{7^0 e^{-7}}{0!} + \displaystyle\frac{7^1 e^{-7}}{1!} +...+ \displaystyle\frac{7^6 e^{-7}}{6!} + \displaystyle\frac{7^7 e^{-7}}{7!} \\\\= 0.59871\approx 0.599](https://tex.z-dn.net/?f=P%28%20x%20%5Cleq%207%29%20%3D%20P%28x%20%3D1%29%20%2B%20P%28x%3D1%29%20%2B...%2B%20P%28x%3D6%29%20%2B%20P%28x%20%3D%207%29%5C%5C%5C%5C%3D%20%5Cdisplaystyle%5Cfrac%7B7%5E0%20e%5E%7B-7%7D%7D%7B0%21%7D%20%2B%20%5Cdisplaystyle%5Cfrac%7B7%5E1%20e%5E%7B-7%7D%7D%7B1%21%7D%20%2B...%2B%20%5Cdisplaystyle%5Cfrac%7B7%5E6%20e%5E%7B-7%7D%7D%7B6%21%7D%20%2B%20%5Cdisplaystyle%5Cfrac%7B7%5E7%20e%5E%7B-7%7D%7D%7B7%21%7D%20%5C%5C%5C%5C%3D%200.59871%5Capprox%200.599)
Thus, 0.599 is the probability that a randomly selected page does not need to be retyped.