What is the standard equation of a circle with center (-2,0) and radius 4?
1 answer:
You might be interested in
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)= where
- Me is the margin of error from the mean
- s is the standard deviation of the population
- N is the sample size
a.
z(p)= ≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)= ≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)= ≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥ where
- N is the sample size
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥ ≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
(b) Expected number of male kitten E(x) = 1
(c) Standard deviation is ±.
Step-by-step explanation:
Given that,
Number of kittens in a group are 10. Out of these 5 are female.
To find:- (a) create a probability model of male kitten chosen.
So, total number of kitten = 10
number of female kitten = 5
then, Number of male kitten =
Now total number of ways to choosing two kittens from group of 10 =
=
=
for choosing (i) No male P(x=0) = P(Two female) =
=
(ii) 1 male P(x=1) = P(1 male and 1 female) = =
=
(iii) 2 male P(x=2)= P(2 male) = =
0 1 2
P(X=)
(b) what is expected number of male kittens chosen ?
Expected number of male kitten E(x) =
=
(c) what is standard deviation ?
No,
=
= ±