The Reciprocal Of 0.25 Is 4
Answer:2x-5y=17;6x-5y=-9
Step-by-step explanation:
Solve equation [2] for the variable x
[2] 6x = 5y - 9
[2] x = 5y/6 - 3/2
// Plug this in for variable x in equation [1]
[1] 2•(5y/6-3/2) - 5y = 17
[1] - 10y/3 = 20
[1] - 10y = 60
// Solve equation [1] for the variable y
[1] 10y = - 60
[1] y = - 6
// By now we know this much :
x = 5y/6-3/2
y = -6
// Use the y value to solve for x
x = (5/6)(-6)-3/2 = -13/2
To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1
F(x) = 2(x)² + 5√(x+2)
f(0) = 2(0)² + 5√(0+2)
= 0 + 5√2
= 5√2
= 7.07 (nearest hundredth)
Answer: 7.07