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Iteru [2.4K]
3 years ago
5

Which expression is equivalent to 3 (x-9) + 6?

Mathematics
2 answers:
vlada-n [284]3 years ago
6 0

Answer: 3x-27

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0

Answer:

3x-21

Step-by-step explanation:

3(x-9)+6

3x-27+6

3x-21

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A toxic radioactive substance with a density of 2 milligrams per square centimeter is detected in the ventilating ducts of a nuc
Zolol [24]

Answer:

60.5 milligrams per square centimeter First, determine how many half lives have expired by dividing the time by the half-life. So: 55/20 = 2.75 That means that only 2^(-2.75) = 0.148650889 = 14.8650889% of the original substance remains. So just divide the amount remaining by 0.148650889 to get the original amount. 9 / 0.148650889 = 60.5445419 So originally, there was 60.5 milligrams per square centimeter 55 years ago.

3 0
4 years ago
A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it
Ymorist [56]

144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Force F=10 lb

From the hookes Law

F=kx

Therefore, calculate k for the spring for

10=k(\frac{4}{12}) = > k=\frac{120}{4}=30

Work done in stretching a spring through a length dx is

dW=F.dx = > dW=kxdx

For calculating the work done for stretching the spring to x=6in=(6/12)feet beyond the natural length, Integrate over the limits of x=0 to x=1/2

Therefore,

\int_{0}^{W}dW=\int_{0}^{0.5}kxdx = > W=\frac{1}{2}k[x^2]_{0}^{0.5}=\frac{1}{2}30 \times (0.5)^2=\frac{30}{8}

That is,

W=\frac{15}{4} ft-lb\\

The answer that is given is for stretching the spring to 4 inches.

Mass of 10 m of chain length is 80kg. This implies, Mass per unit meter length of the chain is

m_{l}=\frac{80}{10}=8kg/m

Consider a small length dx of the chain at the end point A. Work done in lifting the small length dx over the height of x meters is

dW=(8g)dx \times x=8gxdx

Now, integrate over the the value of x from

x=0 when end of the chain A is on the ground

x=6 when end of the chain A reaches 6 m above the ground

That is,

\int_{0}^{W}dW=\int_{0}^{6}8gxdx=8g [\frac{x^2}{2}]_{0}^{6}=4g(6^2-0^2)

W=4g \times 36=144g \ Joules

Hence,144 joules is the work W done in stretching it from its natural length to 13 in beyond its natural length

Learn more about Integration here brainly.com/question/2263647

#SPJ4

7 0
2 years ago
It took Xander 31 minutes to run a 5-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minut
vivado [14]
1 km = 0.621 mile;
5 km = 0.621 * 5 = 3.105 miles;
31 : 3.105 = 9.9838969 ≈ 9.98 minutes
Answer: C ) 9.98 minutes 
3 0
3 years ago
A stack of boards is 24 inches high. each board is 3/4 of and inch thick. How many boards are in the stack?
uranmaximum [27]

Answer:

it would be 18

Step-by-step explanation:

1/4 is 6

2/4 is 12

3/4 is 18

4/4 is 24

You add 6 each time for this one.

7 0
3 years ago
Triangle GHI is similar to triangle JKL. Find the measure of side JK. Round your
ki77a [65]

Answer:

JK = 18.8

Step-by-step explanation:

7/33 = 4/JK

132 = 7JK

JK = 18.86

6 0
3 years ago
Read 2 more answers
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