300 x 1.05 = 315
315 x 1.05 = 330.75
330.75 x 1.05 = 347.2875
347.29
The equation of the line from give points is y = 2/3x - 5/3.
According to the statement
We have given that the two points which are (-2,-3) and (4,1)
And we have to find the equation of a line that passes through the given points.
So,For this purpose,
First, we need to determine the slope of the line. The slope can be found by using the formula:

Where
m is the slope and
Substituting the values from the points in the problem gives:
m = 1 + 3 /4 + 2
m = 4/6
m = 2/3.
And then
Now, we can use the point-slope formula to find an equation for the line. The point-slope formula states:

Put the values in it then
y - (-3) = 2/3 (x-(-2))
y +3 = 2/3 (x +2)
3y + 9 = 2x + 4
3y - 2x = 4 -9
3y -2x = -5
3y = 2x - 5
y = 2/3x - 5/3.
So, The equation of the line from give points is y = 2/3x - 5/3.
Learn more about equation of the line here
brainly.com/question/13763238
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Answer:
-18 C°
Step-by-step explanation:
Warmed means add cooled means subtract
starting at -23 it warmed by 8 add 8
-15
it warmed by 3 more add 3
-12
then it cooled by 6 subtract 6
-18
Answer:
The student is expected to spend <em>15.4 hours </em>doing homework
Step-by-step explanation:
The scattered plot shows there is a close correlation between the variables. A line of best fit will go through the 'center' of the points. Since we are not required to find an exact line, we'll draw it in red color as shown below
To know the equation of that line, we must take two clear points of it from the graph. We'll pick (28,4) and (4,25)
The equation of a line, given two points (a,b) and (c,d) is

Using the selected points

Simplifying and computing results, the equation is

Using that equation, we can predict how many hours the students will spend doing homework if they spend 15 hours watching TV
=15.4 hours
So the student is expected to spend 15.4 hours doing homework
I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).
The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.
The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.