93.5 + 8.7 = 102.2
Hope this helps! :)
6✖35:210
➕4:214
so that is the answer
Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that ![n = 65, \pi = 0.76](https://tex.z-dn.net/?f=n%20%3D%2065%2C%20%5Cpi%20%3D%200.76)
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.76%20-%202.575%5Csqrt%7B%5Cfrac%7B0.76%2A0.24%7D%7B65%7D%7D%20%3D%200.6236)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.76%20%2B%202.575%5Csqrt%7B%5Cfrac%7B0.76%2A0.24%7D%7B65%7D%7D%20%3D%200.8964)
0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
100cm is equivalent to 1m so 500cm is equivalent to 5m. What you need to do is divide 500cm (5metres) by 25cm (one quarter of a metre). So the number sentence using 'division' should look like 500cm divided by 25cm which equals 20. Don't forget to use proper symbols for division though. Let me know if this helps:)
Answer:
25.12 ft that is the answer
Step-by-step explanation: