He sold 12 coins, 16+28+32+4=80. 15% of 80 is 12
Answer:
b=15 g=25
Step-by-step explanation:
lets translate that story problem to mathematics equations
the problem told that no. of girls are 10 more than no of boys so this will =
g=b+10
then in class there are 40 students that means
g+b=40
now we have to equations with two variables then we should substitute
(b+10)+b=40
lets remove the brackets
2b+10=40 subtract 10 from both sides
2b=30 now divide both by 2
b=15 so g=25 after you write the equation once again with the new proof or number
Answer:
9 represents the initial height from which the ball was dropped
Step-by-step explanation:
Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:
The general formula for the geometric progression modelling this scenario is:
Here,
represents the initial height i.e. the height from which the object was dropped.
r represents the percentage the object covers with respect to the previous bounce.
Comparing the given scenario with general equation, we can write:
= 9
r = 0.7 = 70%
i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.
I think it’s D. 102 but it may not be.
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
= (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
