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jarptica [38.1K]
3 years ago
13

If Lamar follows the pattern below how many tiles will he need for his seventh figure the top one

Mathematics
2 answers:
babunello [35]3 years ago
7 0
The pattern here is multiply by 2. Since we can see that the first four numbers are 1, 2, 4, 8, the pattern here is definitely multiply by two. Now, to find the number of tiles he will need in the 7th tile, we will need to raise 2 to the power of something. Since we are multiplying by 2, we are getting different powers of two. The first figure, 1, is two to the power of 0, which means that the power of two for each figure is the figure number minus 1. So, the 7th figure would have 2^{6} tiles which is equal to 64.
elena55 [62]3 years ago
3 0
The answer is D) 64 tiles
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Pls help extra points
Gala2k [10]

Answer:

3

Step-by-step explanation:

3-4-5 the 3  would be it do to the range is 4-5

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3 years ago
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An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How
Nitella [24]

Answer:

There will be 916 ants alive after 4 months.

Step-by-step explanation:

Step 1

Let's change the percentage to a decimal by dividing by a 100.

6.5% / 100 = .065

Step 2

So, for the first month we will multiply the initial amount of ants by .065 and this will give us the number of ants that die.

1200 * .065 = 78

This means that after the first month, 1200 - 78 = 1122 ants will be alive.

Step 3

Now for the second month: 1122 * .065 = 72.93 (rounded to 73)

1122 - 73 = 1049 ants will be alive

Step 4

For the third month 1049 * .065 = 68.185 (rounded to 68)

1049 - 68 = 981 ants will be alive

Step 5

For the fourth month 981 * .065 = 63.765 (rounded to 64)

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5 0
3 years ago
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What is 5.25 as an improper fraction?
Leviafan [203]
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4 0
3 years ago
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Ryan flew from Wiley Post to Ponca City and back. Ryan maintained an average rate of 450 mph going to Ponca City and an average
Reil [10]
The answer is B, and here's why.  Set up a table for "there" and "back" and use the distance = rate * time formula, like this:
               d             r            t
there       d           450         t
back        d           400        1-t

Let me explain this table to you.  The distance is d, we don't know what it is, that's what we are actually looking for.  We only know that if we go somewhere from point A to point B, then back again to point A, the distance there is the same as the distance back.  Hence, the d in both spaces.  There he flew 450 mph, back he flew 400 mph.  If the total distance was 1 hour, he flew an unknown time there and one hour minus that unknown time back.  For example, if he flew for 20 minutes there, one hour minus 20 minutes means that he flew 60 minutes - 20 minutes = 40 minutes back.  See? Now, because the distance there = the distance back, we can set the rt in both equal to each other.  If d = rt there and d = rt back and the d's are the same, then we can set the rt's equal to each other.  450t = 400(1-t) and
450t = 400 - 400t and 850t = 400.  Solve for t to get t = .47058.  Now, t is time, not the distance and we are looking for distance. So multiply that t value by the rate (cuz d = r*t) to get that the distance one way is
d = 450(.470580 and d = 211. 76 or, rounded like you need, 212.
4 0
3 years ago
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