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QveST [7]
4 years ago
9

If the price of a hot dog is $2 and the price of a hamburger is $4, then 30 hot dogs contribute as much to gdp as _____ hamburge

rs. 5 15 30 60 grade it now save & continue continue without saving
Mathematics
2 answers:
Scrat [10]4 years ago
5 0
$2 x 3 = $60
That's the same as $4 x 15
15 hamburgers I'm sure
exis [7]4 years ago
5 0

Solution:

we are given that

The price of a hot dog is $2 and the price of a hamburger is $4.

We have been asked to find

then 30 hot dogs contribute as much to gdp as _____ hamburgers.

Let the required number of hamburgers be x . Then we can write

30*2=4*x\\
\\
60=4x\\
\\
\text{Divide bpoth the sides by 4 we get}\\
\\
x=15\\

Hence the required  number of hamberfgere is 15.

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You would probably need 4 rafts for all of them. 
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Danny paid a total of $13.65 for two steaks that weighed 0.65 lb and 0.75 lb.
nevsk [136]

To find the price per pound, simply add 0.65 + 0.75 then divide.

0.65 + 0.75 = 1.40    13.65 / 1.40 = 9.75

Danny paid $9.75 per pound!

6 0
3 years ago
Read 2 more answers
A triangular pyramid is formed from three right triangles as shown below.
Bess [88]

Answer:

  FH = 108

Step-by-step explanation:

The given figure requires we use the Pythagorean theorem to write two relations involving right triangle side lengths. The Pythagorean theorem tells us the square of the hypotenuse is the sum of the squares of the other two sides.

__

<h3>Triangle EGH:</h3>

  EG² = GH² +HE²

  GH² = EG² -HE² = 53² -28² = 2025 . . . . . solve for GH², use given values

<h3>Triangle FGH:</h3>

  FG² = GH² +FH²

  FH² = FG² -GH² = 117² -2025 = 11664 . . . . solve for FH², use known values

  FH = √11664 = 108 . . . . . take the square root

The length FH is 108.

6 0
3 years ago
Find T, N, and B for the curve at the indicated point. [HINT: After finding T', plug in the specific value for t before computin
lyudmila [28]

Answer:

Step-by-step explanation:

Given that

r(t) = (t,t,e^t)

To find tangent, normal and binormal vectors at (0,0,1)

i) Tangent vector

r'(t) = (1,1,e^t)\\

At the particular point, r'(t) = (1,1,e)

Tangent vector = \frac{r'(t)}{||r'(t)||} \\=\frac{(1,1,e)}{\sqrt{1+1+e^2} } \\=\frac{(1,1,e)}{\sqrt{2+e^2} }

ii) Normal vector

T'(t) = (0,0,e^t)\\

At that point T'(t) = (0,0,e)/e = (0,0,1)

iii) Binormal

B(t) = TX N

= \left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)

8 0
4 years ago
Solve the following
stiv31 [10]
Q1,
A)30 : 3
B)300:3
Q2
A)x=35
B)x=12
Q3
5
8 0
3 years ago
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