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Eddi Din [679]
3 years ago
14

Oh dear lord help me please!!!!!!!!!!!! And tell me how you got your answer please!

Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer:

Hello

Step-by-step explanation:

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White raven [17]

Answer:

40.08

Step-by-step explanation:

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I can't see it can you retake the picture please so I can try to help if I know it?

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After sales tax your brand new car is $17,300. What is the total price of the car with DMV fees of 1.25% of the purchase price o
qwelly [4]

The right answer is Option B.

Step-by-step explanation:

Given,

Purchase price of car with sales tax = $17300

DMV fees = 1.25%

Amount of DMV fees = 1.25% of purchase price

Amount of DMV fees = \frac{1.25}{100}*17300=\frac{21625}{100}

Amount of DMV fees = $216.25

Total price = Purchase price + DMV fees

Total price = 17300 + 216.25

Total price = $17516.25

The total price of car with DMV fees is $17,516.25

The right answer is Option B.

Keywords: percentage, addition

Learn more about addition at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

3 0
4 years ago
The rock has fallen how many feet?
kolbaska11 [484]

Answer:

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4 years ago
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The rate of change of the mass, A, of salt at time t is proportional to the square of the mass of salt present at time t. Initia
Brums [2.3K]

Answer:

(a) -dA/dt = kA², A₀ = 10

(b) A =10/(1+ kt)

(c) t > 60 h

Step-by-step explanation:

(a) Find the IVP

A differential equation with an initial condition y₀ = f(x₀) is called an initial value problem.

The rate of decrease of A is proportional to A², and A₀ = 10, so the IVP is

-dA/dt = kA², A₀ = 10

(b) Solve the IVP

\begin{array}{rcl}-\dfrac{\text{d}A}{\text{d}t} & = & kA^{2}\\\\\dfrac{\text{d}A}{A^{2}} & =&-k\text{d}t\\\\-\dfrac{1}{A} & = & -kt + C\\\\\dfrac{1}{A} & = & kt + C\\\\\end{array}

Apply the initial condition: A₀ = 10 (when t = 0)

\dfrac{1}{10} = C\\\\\dfrac{1}{A} = kt + \dfrac{1}{10}\\\\\dfrac{10}{A} = 10kt + 1\\\\\mathbf{A} = \mathbf{\dfrac{10}{1+ kt}}

(c) Find the time when A(t) < 1

(i) Find the value of k (A₁₀ = 4)

\begin{array}{rcl}A& =&\dfrac{10}{1+ kt}\\\\4 & =& \dfrac{10}{1 + 10k}\\\\4 + 40 k & = & 10\\\\40k & = & 6\\k & = & 0.15\\\end{array}\\\\\mathbf{A} =\mathbf{ \dfrac{10}{0.15t + 1}}

(ii) Find t when A < 1

\begin{array}{rcl}A(t) & < & 1\\\dfrac{10}{0.15t + 1} & < & 1\\\\10 & < & 0.15t + 1\\9 & < & 0.15t\\t & > & 60\\\\\end{array}\\\mathbf{A < 1} \textbf{ when }\mathbf{ t >60}

The figure below shows the graph of A vs t.

6 0
3 years ago
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