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max2010maxim [7]
3 years ago
6

Expand the brackets 7x+5-3(x-4)

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

7x+5-3x+12

7x-3x+12+5

4x+17

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Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
2 years ago
Solve the proportion: 35/8 = 105/x
dangina [55]

Answer:

x=24

Step-by-step explanation:

6 0
2 years ago
6.875 rounded to the nearest gram
zhenek [66]

Answer: 6.9

Step-by-step explanation: Find the number in the tenth place 8

and look one place to the right for the rounding digit 7. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

6.9

7 0
2 years ago
What is the 103rd term of the arithmetic sequence
UNO [17]

Answer:

option B: 31/4

Step-by-step explanation:

Given

-3/4, -2/3 , -7/12, -1/2...........

General formula for arithmeti sequence to find nth term is

a_n = a_1 + (n-1) d

first term a_1 = -3/4

We find out common difference 'd'

Lets find the difference of first two terms

\frac{-2}{3} -\frac{-3}{4} = \frac{-8}{12} +\frac{9}{12} =\frac{1}{12}

common difference is 1/12

now we need to find 103rd term

a_n = a_1 + (n-1) d

First term is -3/4, d= 1/12

a_{103} = \frac{-3}{4}+(103-1)\frac{1}{12}

a_{103} = \frac{-3}{4}+(102)\frac{1}{12}

a_{103} = \frac{-3}{4}+\frac{34}{4}

a_{103} = \frac{-3+34}{4}

a_{103} = \frac{31}{4}

5 0
2 years ago
Read 2 more answers
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