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lisabon 2012 [21]
3 years ago
8

Write the equation of the function. is it y = x2 / 6 - 3x /2 + 13/3 ?

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0

Yo sup??

Since there is an x^2 term therefore this equation is of a parabola

By taking LCM and then cross multiplying it.

6y=x^2-9x+26

6y=x^2-9x+(9/2)^2+23/4

6y-23/4=(x-9/2)^2

we see that this is of the form

X^2=4AY

(x-9/2)^2=4(3y/2-23/16)

Hope this helps.

zmey [24]3 years ago
6 0

Answer:

f(x) =- \sqrt{x-1}+3

Step-by-step explanation:

This looks like a square root function f(x) = \sqrt{x}  but symmetric with respect to the x axis and shifted to the right for 1 and up for 3:

Lets take  f(x) = \sqrt{x} . The function symmetric with respect to the x axis would be -f(x), so now we have:

                                                f(x) = -\sqrt{x}

Lets take f(x) = -\sqrt{x} and shift it up for y = 3. Now we have:

                                               f(x) =- \sqrt{x}+3

Lets take f(x) = -\sqrt{x}+3 and shift it right for x = 1. That means that instead of x we will have x-1:

                                            f(x) =- \sqrt{x-1}+3

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i) In this case, we understand that vertex P = (-5,-3) changed to P' = (5,3) after doing an operation. At first we must calculate the distance of each point regarding origin by Pythagorean Theorem:

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