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lisabon 2012 [21]
3 years ago
8

Write the equation of the function. is it y = x2 / 6 - 3x /2 + 13/3 ?

Mathematics
2 answers:
gayaneshka [121]3 years ago
7 0

Yo sup??

Since there is an x^2 term therefore this equation is of a parabola

By taking LCM and then cross multiplying it.

6y=x^2-9x+26

6y=x^2-9x+(9/2)^2+23/4

6y-23/4=(x-9/2)^2

we see that this is of the form

X^2=4AY

(x-9/2)^2=4(3y/2-23/16)

Hope this helps.

zmey [24]3 years ago
6 0

Answer:

f(x) =- \sqrt{x-1}+3

Step-by-step explanation:

This looks like a square root function f(x) = \sqrt{x}  but symmetric with respect to the x axis and shifted to the right for 1 and up for 3:

Lets take  f(x) = \sqrt{x} . The function symmetric with respect to the x axis would be -f(x), so now we have:

                                                f(x) = -\sqrt{x}

Lets take f(x) = -\sqrt{x} and shift it up for y = 3. Now we have:

                                               f(x) =- \sqrt{x}+3

Lets take f(x) = -\sqrt{x}+3 and shift it right for x = 1. That means that instead of x we will have x-1:

                                            f(x) =- \sqrt{x-1}+3

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Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solut
Inessa05 [86]

The equation is 0.1x + 0.15(50-x)=1.20(50)

Step-by-step explanation:

Here you need 50ml of 12% alcohol solution.

You have 10% and 15% alcohol solutions.

Take volume of 10% alcohol solution to be x ml

Take volume of 15% alcohol solution to be y ml

Form equations;

x+y=50 ml--------------------------equation 1

0.1x +0.15 y= 12% of 50

0.1x+0.15y=6-----------------------equation 2

Now you have simultaneous equations, use a graph tool to solve for values of x and y as attached.

or use the mixture equation the get value of x

0.1x + 0.15(50-x)=1.20(50)

The values of x and y are ;

(x,y) (30,20) which means;

y is 20 ml of 15% alcohol

x is 30 ml of 10% alcohol

Learn More

  • brainly.com/question/2405496

Keywords : concentration, mixture

#LearnwithBrainly

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