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dybincka [34]
3 years ago
9

Can someone please answer this worksheet for me. I would be really thankful if you do so. ​

Mathematics
1 answer:
zhenek [66]3 years ago
6 0
I know 1 but I don’t know 2

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What is the area of the circle below?<br> 10 ft
azamat

Answer:

<h3>Circle</h3>

Solve for area

A=π r^2

r =Radius

<h2>You about this first: </h2>

The circumference of a circle is its perimeter or distance around it. It is denoted by C in math formulas and has units of distance, such as millimeters (mm), centimeters (cm), meters (m), or inches (in). It is related to the radius, diameter, and pi using the following equations: C = πd. C = 2πr.

Step-by-step explanation:

Hope it is helpful....

8 0
3 years ago
What measurement is equal to 6 kilometers
salantis [7]

Answer:

where is the options? or is any given.

Step-by-step explanation:

4 0
3 years ago
Select the equation written in standard form.
Elden [556K]

Answer:

c

Step-by-step explanation:

standard form is y=mx+b

5 0
3 years ago
Type the correct answer in each box.
Mariulka [41]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)    

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

r=\sqrt{(2+4)^{2}+(-3-5)^{2}}

r=\sqrt{(6)^{2}+(-8)^{2}}

r=\sqrt{100}\ units

r=10\ units

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center

r is the radius

we have

(h,k)=(5,-4)\\r=10\ units

substitute

(x-5)^2+(y+4)^2=10^2

(x-5)^2+(y+4)^2=100

6 0
3 years ago
A slow pitch softball diamond is actually a square 60 ft on a side. how far is it from home to second ​base?
krek1111 [17]
For this case we have a square whose sides are known and equal to 60 ft.
 We want to find the diagonal of the square.
 For this, we use the Pythagorean theorem.
 We have then:
 d^2 = 60^2 + 60^2&#10;&#10;d =  \sqrt{60^2 + 60^2}&#10;&#10; d =  \sqrt{3600 + 3600}&#10;&#10;d = \sqrt{2*3600}&#10;&#10;d = 60\sqrt{2}&#10;
 Answer:
 
from home to second ​base it is about:
 d = 60\sqrt{2} feet
3 0
3 years ago
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