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GaryK [48]
3 years ago
7

How to make an experssion of a tip and the costs of a meal

Mathematics
1 answer:
rewona [7]3 years ago
6 0
Just be kind n smile back at the waiter or waitress for serving your food n if the food presented nicely don't hesitate to give s nice tip
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For the diagram below figure b is a reflection of y=2x of the line y =x
Scilla [17]
The equation of the line would be y = (1/2)x.

To find the equation of a line that is reflected through the line y = x, we just switch the x and y. Then, solve for y.

y = 2x
x = 2y
0.5x = y


5 0
3 years ago
Someone help me with this please, I really need help, and it's due tmrw...PLEASE
levacccp [35]

Answer:

the last one

Step-by-step explanation:

3.5(w) 3.5 per week or 3.5 change per week

hope this was helpful

3 0
3 years ago
Read 2 more answers
During statistical analysis, the investigator may consider searching for statistical associations among various groups that may
IceJOKER [234]

.

Answer:

This is known as Data dredging.

Step-by-step explanation:

In order for any statistical analysis to be significant, a researcher has to first generate a hypothesis.  

Data dredging is trying to uncover patterns in data that can be presented statistically without devising a clear hypothesis by use data mining.  It is also referred to as data fishing or p-hacking.  

In this case any correlation (relationship between cause-effect)will be purely by chance.

Therefore, the investigator is Data dredging

3 0
3 years ago
What is the greatest common factor of 44c5,22c3 and 11c4?
elena-s [515]

Answer:

The greatest common factor of the given expressions is

11c^3

Step-by-step explanation:

Given that 44c^5,22c^3,11c^4

44c^5 can be written as

11\times 4\times c^3\times c^2

22c^3 can be written as  

11\times 2\times c^3

and  11c^4 can be written as

11\times 1\times c^3\times c

Comparing the common factors we have 11\times c^3 is the greatest common factor of 44c^5,22c^3,11c^4

Therefore the greatest common factor of the given expressions is

11c^3

3 0
3 years ago
there are 53 oranges in a box that contains a total of 77 pieces of fruit. how many oranges need to be added so that the box con
Tju [1.3M]
Ok so do 100 divided by 77 to get about 1.3% per fruit. then do 1.3 times 53 to get the current percent of oranges which is about 69% then do 84% minus 69% to get the difference then divide by 1.3 to get about 11.5 oranges so you round to 12 oranges. So 12+53 to get 65 total oranges to equal 84% of the 77 fruit in the box.
6 0
3 years ago
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