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romanna [79]
3 years ago
7

What integer represents saving $65?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
8 0

Answer:

+$65

Step-by-step explanation:

We are asked to determine the integer that represents saving $65.

We know that savings represent a positive number. Savings stands for the amount saved by a person.

We know that loss, withdraw and spend represent negative quantities, while the savings, profit  and deposit represent positive quantities, therefore, saving of $65 would be +$65.

-BARSIC- [3]3 years ago
4 0
I feel very wrong but I think |65| sorry, I just started learning absolute value and integers and I am bad at math
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A gardening center is planting trees for sale. Until the trees are fully grown, employees need to put rope
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Determine if the two triangles are congruent. If they are, state how you know.
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Read 2 more answers
Determine the intercepts of the line that passes through the following points. (-5,-7) (0,-5) (5,-3)
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To find the y intercept you use this equation:

y2 - y1

Same for x intercept:

x2 - x1

Pick two points, put in the values, and solve.

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The y intercept is (0,2)
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Hope this helps! :)
-Peredhel
4 0
3 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\


\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
2 years ago
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