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Sav [38]
3 years ago
9

Solve the quadratic equation x2 - x = 30 by completing the square

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Given

x² - x = 30

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- \frac{1}{2})x + \frac{1}{4} = 30 + \frac{1}{4}

(x - \frac{1}{2})² = \frac{121}{4}

Take the square root of both sides

x - \frac{1}{2} = ± \sqrt{\frac{121}{4} } = ± \frac{11}{2}

Add \frac{1}{2} to both sides

x = \frac{1}{2} ± \frac{11}{2}, thus

x = \frac{1}{2} - \frac{11}{2} = - 5

x = \frac{1}{2} + \frac{11}{2} = 6

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Answer:

a) 2b = 3g

b) 3p = b

Step-by-step explanation:

Given:

Fire hydrant with a blue cap, b, provides water at a rate = 1500 gallons per min

Fire hydrant with a green cap, g, provides water at a rate = 1000 gallons per min

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a) The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

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Simplifying, we have:

b = 3*500

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Since the flow rate of green hydrant, g, is 1000, let's replace 1000 with g above.

Therefore,

b = 3 * \frac{g}{2}

b = \frac{3}{2}g

Cross multuply

2b = 3g

The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g is 2b=3g.

b) An equation to relate the flow of water from the purple hydrant, p, to the flow from the blue hydrant, b.

Given flow rate of purple hydrant, p = 500

It could also be re-written as:

\frac{3}{3} * 500

p = \frac{1500}{3}

Since the flow rate of blue hydrant, b, is 1500, let's replace 1500 with b above.

p = \frac{b}{3}

Cross multiply

3p = b

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-5 * 4 + 22 = 2

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