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Sav [38]
3 years ago
9

Solve the quadratic equation x2 - x = 30 by completing the square

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Given

x² - x = 30

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- \frac{1}{2})x + \frac{1}{4} = 30 + \frac{1}{4}

(x - \frac{1}{2})² = \frac{121}{4}

Take the square root of both sides

x - \frac{1}{2} = ± \sqrt{\frac{121}{4} } = ± \frac{11}{2}

Add \frac{1}{2} to both sides

x = \frac{1}{2} ± \frac{11}{2}, thus

x = \frac{1}{2} - \frac{11}{2} = - 5

x = \frac{1}{2} + \frac{11}{2} = 6

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In two gallons would be 8 quarts.

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Note: 3 quarts is 3/4 or .75 of a gallon.
6 0
3 years ago
Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.
Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

y=ax^2+bx+c

Here the vertex of an up - down facing parabola has a form of,

x_v=-\dfrac{b}{2a}

The parameters we have are,

a=-5,b=-10, c=6

Plug them in vertex formula,

x_v=-\dfrac{-10}{2(-5)}=-1

Plug in the x_v into the equation,

y_v=-5(-1)^2-10(-1)+6=11

We now got a point parabola vertex with coordinates,

(x_v, y_v)\Longrightarrow(-1,11)

From here we emerge two rules:

  • If a then vertex is max value
  • If a>0 then vertex is min value

So our vertex is minimum value since,

a=-5\Longleftrightarrow a

Hope this helps.

r3t40

7 0
3 years ago
5y-x=10 solve for y
shusha [124]
5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

because
5y-x=5(2+\frac{x}{5})-x=5\cdot 2 +\frac{x}{\not5}\cdot 5 - x= 10+x-x=10



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wo mechanics worked on a car. The first mechanic charged $95 per hour, and the second mechanic charged $75per hour. The mechanic
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5 hours and 25 minutes I think (Im not sure)

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Answer:

8.2

Step-by-step explanation:

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