Which equation or inequality below is true??

Mathematics

1 answer:

dedylja [7]3 years ago

5 0

If it's got the symbol: "=" in it, then it's an education

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Fractional indices pls help

bulgar [2K]

Answer:

Formula used :

(a^m)^n = a^(m×n)
a^m × a^n = a^(m+n)

$27 \times {9}^{3x} = {3}^{k} \\ {3}^{3} \times { {(3}^{2}) }^{3x} = {3}^{k} \\ {3}^{k} = {3}^{3} \times {3}^{(2 \times 3x)} \\ {3}^{k} = {3}^{3} \times {3}^{6x} \\ {3}^{k} = {3}^{(6x + 3)} \\ \boxed{k = 6x + 3}$

<u>k = (6x+3)</u> is the right answer.

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3 years ago

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Shalnov [3]

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3 years ago

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3 years ago

Shiloh has to earn at least $200 to meet her fundraising goal. She has only 100 cakes that she plans to sell at 5 dollars each.

kakasveta [241]

Here is the inequality you can enumerate:

5x >= 200, this means the money you sold for cakes must be larger or equal to your goal

x <= 100, this means you cannot sell more than 100 cakes, because you only have 100 cakes

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3 years ago

E + 1 13/16 = 2 5/16

Burka [1]

e + 1 13/16 = 2 5/16

subtract 1 13/16 from each side

e = 2 5/16 - 1 13/16

borrow from the 2

e = 1 16/16 + 5 /16 - 1 13/16

e = 1 21/16-1 13/16

e = 1 8 /16

e = 1 1/2

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3 years ago