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xxTIMURxx [149]
3 years ago
13

If it is 2:30 what time would it be 1 hour and 30 minutes

Mathematics
2 answers:
lawyer [7]3 years ago
4 0

Answer:

4:00

Step-by-step explanation:

german3 years ago
3 0
If it’s 2:30 it would be 4:00 in an hour and a thirty minutes ahead
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Simplify the radical expression by rationalizing the denominat o 3/11
8090 [49]
Do you mean 3/√11 ? In this case, you'll have to multiply both, numerator and denominator by the denominator ... 
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3 years ago
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Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad battery life. Batt
BartSMP [9]

Answer:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

H_o: \sigma _1 ^2 \leq \sigma _2^2

Alternative hypothesis: the variance  in hours of usage for talking is  greater than the the variance in hours of usage for internet.

H_a : \sigma_1^2 > \sigma_2^2

\mathbf{s_ 1 =16.11}

\mathbf{s_2 = 7.98}

Step-by-step explanation:

Let x_1 and x_2 be the two variables that represents the battery life in hours for talking usage and battery life in hours for internet usage respectively.

The hypothesis can be formulated as:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

H_o: \sigma _1 ^2 \leq \sigma _2^2

Alternative hypothesis: the variance  in hours of usage for talking is  greater than the the variance in hours of usage for internet.

H_a : \sigma_1^2 > \sigma_2^2

The standard deviation for the battery usage for talking is :

\bar x_1 = \dfrac{1}{n_1} \sum x_i  \\ \\ \bar x_1  = \dfrac{1}{12}(35.8 +22.4+...+35.5) \\ \\ \bar x_1 = \dfrac{241.2}{12}  \\ \\ \bar x_1 =20.1

The standard deviation Is:

s_ 1 = \sqrt{\dfrac{1}{n_1-1}\sum (x{_1i}-\bar x_i)^2}

s_ 1 = \sqrt{\dfrac{1}{12-1}\sum (35.8- 20.1)^2+ (35.5-20.1)^2}

s_ 1 = \sqrt{259.568}

\mathbf{s_ 1 =16.11}

The standard deviation for the battery life usage for the internet is :

\bar x_2 = \dfrac{1}{n_2} \sum x_{2i}

\bar x_2 = \dfrac{1}{10} (24.0+12.5+36.4+...+4.7})

\bar x_2 = \dfrac{115}{10}

\bar x_2 = 11.5

Thus; the standard deviation is:

s_2 = \sqrt{\dfrac{1}{n_2-1}(x_{2i}- \bar x_2)^2}

s_2 = \sqrt{\dfrac{1}{10-1}(24-11.5)^2+(4.7-11.5)^2}

s_2 = \sqrt{63.60}

\mathbf{s_2 = 7.98}

4 0
3 years ago
Prediction: It rains 2 out of the last 12 days in March. If this trend continues, how many rainy days would you expect in April?
Vladimir79 [104]

Answer:

I would expect rain 5 days

Step-by-step explanation:

Please kindly see the attached files for explanation.

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The owner of a landscaping business wants to know how much time,on average, his workers spend mowing one lawn. Which is the most
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4. Hours per lawn would be the answer
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1/3 (9 - 6x) = x Solve the following please
Dmitriy789 [7]
Hello there!

1/3 (9 - 6x) = x

Start by using the distributive form

(1/3)(9) + (1/3)(-6x) = x

9/3 + (-6x)/3 = x

3 - 2x = x

-2x + 3 = x

-2x - x + 3 = 0

-3x + 3 = 0

-3x = 0 - 3

-3x = -3

x = -3/-3

x= 1

It is always my pleasure to help people like you. As always, I am here to help!
7 0
4 years ago
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