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sertanlavr [38]
3 years ago
8

There are 18,017 AIDS deaths in 2003, or 34.5% of the 1995 AIDS deaths. Determine the number of AIDS deaths in 1995.

Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer: There are 52223.18 AIDS death in 1995.

Step-by-step explanation:

Since we have given that

Number of AIDS deaths in 2003 = 18,017

Percentage of deaths of 1995 AIDS deaths =34.5%

Let the number of AIDS deaths in 1995 be 'x'.

According to question, it becomes ,

\dfrac{34.5}{100}\times x=18017\\\\x=18017\times \dfrac{100}{34.5}\\\\x=52223.18

Hence, there are 52223.18 AIDS death in 1995.

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