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Genrish500 [490]
2 years ago
10

1/2 (b - 10) + 2b = 25

Mathematics
2 answers:
Pepsi [2]2 years ago
8 0

Answer:

b=12

Step-by-step explanation:

1/2 (b - 10) + 2b = 25

Multiply each side by 2 to get rid of the fractions

2*1/2 (b - 10) +2* 2b = 25*2

b-10 +4b = 50

Combine like terms

5b -10 = 50

Add 10 to each side

5b -10+10 = 50+10

5b = 60

Divide by 5

5b/5 = 60/5

b = 12

Serggg [28]2 years ago
4 0

Answer:

the answer is 12

Step-by-step explanation:

Simplify both sides of the equation.

12(b−10)+2b=25

(12)(b)+(12)(−10)+2b=25(Distribute)

12b+−5+2b=25

(12b+2b)+(−5)=25 (Combine Like Terms)

52b+−5=25

52b−5=25

add 5 to both sides.

52b−5+5=25+5

52b=30

multiply both sides by 2/5.

(25)*(52b)=(25)*(30)

b=12

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Let the score of cowboys is x
and giants make score 9 which is twice less than the cowboys score so
giants score will be = 2x -9
and packers scored 14 more than giants that is (2x - 9) + 14
now sum of their scores is equal to 81 it means:
x + (2x - 9) + (2x -9) + 14 = 81
x + 2x - 9 + 2x - 9 + 14 = 81
5x = 81 + 4
5x = 85
x = 17
packers scored =  (2x - 9) + 14
= 2 (17) -9 + 14
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5 0
3 years ago
Write an equation of a line parallel to y=10x+6 and going through point (2,-4)
nadya68 [22]

Answer:

Y= 10x-24 would be parralel to y=10x+6

Step-by-step explanation:

well a parralel line has to have the same slope and a different y-intercept.

To find the y-intercept the x has to be exactly 0.

So we have (2,-4)

The slope is 10/1 which is 10y and 1 x which in an ordered park would be Add 1 x and add 10 y. But we’re trying to get x to be 0 to find the y-intercept.

So subtract 1 x and subtract 10y

2-1=1

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THe y-intercept is -24 and w have the slope since its the same thing So

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7 0
3 years ago
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masha68 [24]

Answer:

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Step-by-step explanation:

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2 years ago
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AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} 
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1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\
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3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ 
4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\
5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ 
6. \angle ABD\cong\angle BAE & 6. Alternate angles
\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}
7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\
8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\
9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\
11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] 
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7 0
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2 right 3 up... hope this helped you
7 0
3 years ago
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