The probability of selection 2 black cups one after another one without replacement is 1/91
<h3>What is the probability of selection 2 black cups one after another one without replacement?</h3>
The given parameters are:
Green = 4
Blue = 8
Black = 2
Given that the selection is without replacement, this means that the number of cups reduces when one is selected
So, we have:
P(2 Black cups) = P(Black) * P(Black)
This gives
P(2 Black cups) = 2/(4 + 8 + 2) * (2 - 1)/(4 + 8 + 2 - 1)
Evaluate
P(2 Black cups) = 2/14 * 1/13
This gives
P(2 Black cups) = 1/91
Hence, the probability of selection 2 black cups one after another one without replacement is 1/91
Read more about probability at
brainly.com/question/24756209
#SPJ1
Well what grade are you in cause I’m also learning some of this stuff, I actually learned it before at t(e beginning of the year
Answer:
36
Step-by-step explanation:
ik it bc im smart
You basically plug in numbers..I will use positive integers.
You basically plug in numbers for x to find the y .
0,1
1,-2
2,-5
3,-8 and so on
