0.77 the digit in the tens place is how many times is the value of the digit in the hundreds place

Mathematics

1 answer:

krek1111 [17]3 years ago

4 0

*Tenths and *hundredths
The digit in the tenths place is 10 times the digit in the hundredths place. hope this helps.

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Refer to the photo :D

OlgaM077 [116]

well, we know the ceiling is 6+2/3 high, and Eduardo has 4+1/2 yards only, how much more does he need, well, is simply their difference, let's firstly convert the mixed fractions to improper fractions and then subtract.

$\stackrel{mixed}{6\frac{2}{3}}\implies \cfrac{6\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{20}{3}} ~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{20}{3}-\cfrac{9}{2}\implies \stackrel{using ~~\stackrel{LCD}{6}}{\cfrac{(2\cdot 20)-(3\cdot 9)}{6}}\implies \cfrac{40-27}{6}\implies \cfrac{13}{6}\implies\blacktriangleright 2\frac{1}{6} \blacktriangleleft$

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2 years ago

I need help ok help meeee

uysha [10]

It’s a bit blurry retake the picture

7 0

3 years ago

I need help with this problem ASAP

omeli [17]

Answers: 7x^2y^2 -3x+6y

I am not sure how to explain it but here you go

7 0

2 years ago

What is the length of chord An in Oo below?

Anika [276]

Answer:

12 units

Step-by-step explanation:

$In\: \odot O,$

chords $\overline{ML}$ and $\overline{AN}$ are equidistant (7.2 units) from the center of the circle O.
Measures of the chords equidistant from the center of the circle are equal.
$\therefore m(chord\:\overline{AN}) =m(chord\:\overline{ML})$
$\because m(chord\:\overline{ML}) = 12\: units$
$\therefore m(chord\:\overline{AN}) = 12\: units$

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2 years ago

Correct answer gets brainliest and 5 stars

Serggg [28]

Answer:

A is false

Step-by-step explanation:

notice how in both diagrams, there are 4 triangles with lengths a, b, c, but in each diagram the triangles are just rotated and positioned differently. if there are the same amount of triangles in both diagrams, and the have equal lengths then the area of the remaining figure, should both match up.

basically the area of the big square in Step 2, is equal to both of the shaded squares, combined area, in Step 1.

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2 years ago