Answer:
3
Step-by-step explanation:
The length of OM is 4/3 the length of OJ, and the length of ON is 4/3 the length of OK. Thus, two pairs of sides from the triangles are proportional to each other.
Also, angle O from one of the triangles is equal to angle O of the other triangle because they are the same angle.
Thus, the two triangles are similar by SAS (side-angle-side) similarity theorem. This theorem is quite similar to the SAS congruence theorem.
To make a similarity statement, we just have to match corresponding parts when naming the triangle.
Similarity statement: ΔOJK~ΔOMN
Answer: 348
Step-by-step explanation:
Given : Total employees work = 725
Proportion of employees are post graduate = 52%
Proportion of employees are not post graduate = 100%-52% = 48%
The number of employees were not post graduate = 48% of 725
= 0.48 x 725
= 348
Hence, the number of employees were not post graduate = 348
Answer:
A.8 B.(-1,4) C.(1,4)
Step-by-step explanation:
First, know that (3,2)=(x1,y1) and (-5,6)=(x2,y2)
A. The diameter is 8, given the diference between x1 and x2: 3-(-5)=8
B. The center point is given by (x1+x2)/2 and (y1+y2)/2
(x1+x2)/2 and (y1+y2)/2 = (3-5)/2 and (2+6)/2 = (-1,4)
C. The symmetric point of C about the x-axis is (1,4)
Answer:
d) All of the above
Step-by-step explanation:
A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).
In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.
In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.
This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.
The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.
Let's say we are comparing the means of k population. The degree of freedom would be = k - 1
The correct option here is (d).
All of the above