18/10
9/5
Anything along those lines!
Answer:
1436 i believe
Step-by-step explanation:
Answer:
The series
1 -0.5-2-3.5 -5-6.5-8-9.5-11-12.5-14-15.5 upto 12 terms
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given series 1 -0.5 -2 +.........
we know that the sum of the sequence is called a series
The sequence is 1, -0.5, -2, -3.5,.....is in AP
a = 1 and the difference between the two terms is equal 'd' = -1.5
<u><em>Step(ii):-</em></u>
<u><em>adding 1.5 value of each term</em></u>
The series
1 -0.5-2-3.5 -5-6.5-8-9.5-11-12.5-14-15.5 upto 12 terms
<u><em></em></u>
Answer:
k = -2
Step-by-step explanation:
2 way to solve:
1st: 8x²-13x-4k = 8(x²-(13/8)x-(k/2))
if 2 roots: a and 1/a
8(x-a)(x-1/a) = 8(x²-(13/8)x-(k/2))
x²-(a+1/a)x+1 = x²-(13/8)x-(k/2)
1 = -(k/2)
<u>k = -2</u>
<u>2nd:</u> 2 roots of 8x²-13x-4k x=(-b±√b²-4ac)/2a
x = (13±√169-4*8*(-4k))/16 = (13±√169+128k)/16
(13+(√169+128k))/16 = 16/ (13-(√169+128k)) ... root1=1/root2
(13+(√169+128k))*(13-(√169+128k)) = 16*16
13² - (√169+128k)² = 256
169-169-128k = 256
-128k = 256
k = -2
