<h2>3.14 units²</h2><h3><em>(Assuming pi equals 3.14)</em></h3><h3><em></em></h3><h3>A = pi(radius²)</h3><h3></h3><h3>1² = 1</h3><h3>1 x 3.14 = 3.14</h3>

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2 years ago

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Graph a line with a slope of 1/4 that contains the point (6, 3).

Semenov [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

$y-y1=m(x-x1)$

we have

$(x_1,y_1)=(6,3)$

$m=\frac{1}{4}$

substitute

$y-3=\frac{1}{4}(x-6)$

The easiest way to graph a line is to calculate the intercepts

The<u><em> x-intercept </em></u>is the value of x when the value of y is equal to zero

For y=0

$0-3=\frac{1}{4}(x-6)$

$-12=(x-6)$

$x=-12+6=-6$

The x-intercept is the point (-6,0)

The <u><em>y-intercept</em></u> is the value of y when the value of x is equal to zero

For x=0

$y-3=\frac{1}{4}(0-6)$

$y-3=-\frac{3}{2}$

$y=-\frac{3}{2}+3$

$y=1.5$

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

8 0

2 years ago