Answer:
The solution is:
![-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}](https://tex.z-dn.net/?f=-7r-4%5Cge%20%5C%3A%5C%3A4r%2B2%5Cquad%20%5C%3A%3A%5Cquad%20%5C%3A%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-0.54545%5Cdots%20%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%5C%3A%2C%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5D%5Cend%7Bbmatrix%7D)
Please check the attached line graph below.
Step-by-step explanation:
Given the expression

Add 4 to both sides

Simplify

Subtract 4r from both sides

Simplify

Multiply both sides by -1 (reverses the inequality)

Simplify

Divide both sides by 11

Simplify

Therefore, the solution is:
![-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}](https://tex.z-dn.net/?f=-7r-4%5Cge%20%5C%3A%5C%3A4r%2B2%5Cquad%20%5C%3A%3A%5Cquad%20%5C%3A%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ar%5Cle%20%5C%3A%5C%3A-0.54545%5Cdots%20%5C%3A%5C%5C%20%5C%3A%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%5C%3A%2C%5C%3A-%5Cfrac%7B6%7D%7B11%7D%5D%5Cend%7Bbmatrix%7D)
Please check the attached line graph below.
Answer:
I could only find a single semi-complete question on that paper due to the quality of the picture. <u>The carbon dioxide and water escape from the tube, because as gases, they do not have a definite shape or volume, and instead expand to fit whatever container they are in.</u>
Hope it helps
Width = w
length = w+2
f(w) =w(w+2) = w^2 + 2w.
Please, let me know whether the procedure is clear for you.
The answer is f(w)=w^2 + 2w.
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
6 items for $14.34 each is $86.04.