Simply the problem.
2 answers:
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Answer:
53
Step-by-step explanation:
Given: The sum of two digit number is 8
Reversing the digit will get us number 18 less than the original.
Lets take x as tenth digit of our number and y as unit digit of our number.
As given sum of digit is 8
∴
∴ - equation 1
We also know that reversing the digit will get us number 18 less than the original.
∴
Now, lets put the value of y from equation 1
⇒
⇒
⇒
∴
Next, substituting the value of x in equation 1
⇒
∴
∴ The original number is 53, sum of the digit is 8 and if we reverse the digit of the number, we get 35, which is 18 less than the original number.
Step-by-step explanation:
there 5^(n+1) + 5^(n+2) = 5^n x 5^1 + 5^n x 5^2 breaking them as x^(a+b) = x^a x x^b
then taking common 5^n from both terms
