Answer:
a) r(q) = 1000(q +1/q)
b) r'(q) = 1000(1 -1/q^2)
c) r'(10) = 990
Step-by-step explanation:
a) Revenue is the product of quantity and price:
r(q) = q·p(q) = q(1000(1 +1/q^2))
r(q) = 1000(q + 1/q)
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b) The derivative is ...
r'(q) = 1000(1 -1/q^2)
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c) The derivative evaluated for q=10 is ...
r'(10) = 1000(1 -1/10^2) = 1000(0.99)
r'(10) = 990
Given that the function g(x)=x-3/x+4, the evaluation gives:
- g(9) = 6/13.
- g(3) = 0.
- g(-4) = undefined.
- g(-18.75) = 1.07.
- g(x+h) = x+h-3/x+h+4
<h3>How to evaluate the function?</h3>
In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:
When g = 9, we have:
g(x)=x-3/x+4
g(9) = 9-3/9+4
g(9) = 6/13.
When g = 3, we have:
g(x)=x-3/x+4
g(3) = 3-3/3+4
g(3) = 0/13.
g(3) = 0.
When g = -4, we have:
g(x)=x-3/x+4
g(-4) = -4-3/-4+4
g(-4) = -1/0.
g(-4) = undefined.
When g = -18.75, we have:
g(x)=x-3/x+4
g(-18.75) = -18.75-3/-18.75+4
g(-18.75) = -15.75/-14.75.
g(-18.75) = 1.07.
When g = x+h, we have:
g(x)=x-3/x+4
g(x+h) = x+h-3/x+h+4
Read more on function here: brainly.com/question/17610972
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Well u need to give me the equation and the substitutions for the variables then I can solve it
Sorry, but I have no idea what your "<span>eaqkesbnnn" means.
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If you were supposed to add 0.16 and 0.45, the correct answer would be 0.61.
Answer:
6v+16
Step-by-step explanation:
2(2v+13) + 2(v-5) > 4v+26+2v-10 > 6v+16
