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omeli [17]
3 years ago
12

What is a reasonable estimate for the product 43 times 68

Mathematics
2 answers:
kupik [55]3 years ago
8 0
A reasonable answer would be 2800 because 40x70. 
dsp733 years ago
7 0
43 times 68.

43
x68

8 times 3 is 24. Bring the 2 over the 4.
8 times 4 is 32. Add 4. Equals 36.
Answer so far is 364.

Add a 0 before answering.
3 times 6 is 18. Bring the 1 over the 4.
4 times 6 is 24. Add 4. Equals 28.
Answer so far is 288

Add 364 + 288
Final answer is 652.
You might be interested in
Which inequality has -25 in its solution set?
Ann [662]

Many inequalitys have -25 in their solution sets.

There are too many to name.

5 0
3 years ago
find two consecutive odd intergers that twice the larger is fifteen more than three times the smaller
Svetach [21]

Answer:

11, 13

Step-by-step explanation:

an odd number can be represented by 2n+1

since they are consecutive, the larger odd number will be 2n + 1 + 2

now,

2(2n+3) = 2n + 1 +15

solving this eqn, we get n = 5

so the two numbers are (2n+1) = 11 and 11+2= 13

4 0
3 years ago
Read 2 more answers
If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
2 years ago
At noon, Bradley began steadily increasing the
barxatty [35]

Answer:

25.5 mph

Step-by-step explanation:

So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed

So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15

y=2(0.25)+40

y=0.5+40

y=40.5

So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed

40.5 - 15 = 25.5

8 0
2 years ago
Read 2 more answers
K(t) = 13t – 2<br> k(3) =
Maru [420]
Since t=3

What do have to do is just set it for 3.

13(3) -2

k(3) = 37
4 0
3 years ago
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