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photoshop1234 [79]
3 years ago
8

A toy box contains eight green balls and four purple balls. Suppose you choose a ball at random and then replace it by putting i

t back in the toy box. You then choose a second ball. What is the probability that you have selected a green ball and then a purple ball?
Option A: 2/9
Option B: 1/2
Option C: 1/3
Option D: 2/3
Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer: C.  \dfrac{1}{3}

Step-by-step explanation:

Given: Box contains 8 green balls and 4 purple balls.

Total balls = 8+4 = 12

event 1 = first picking green ball

event 2 = second picking purple balls.

As first ball was replaced, that means both events are independent.

Probability that you have selected a green ball and then a purple ball = P(purple ball )

Formula for probability = \dfrac{\text{favorable outcomes}}{\text{total outcomes}}

Probability of selecting a purple ball (second pick)= \dfrac{4}{12}

=\dfrac{1}{3}

The required probability =\dfrac{1}{3}, so C is correct option.

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