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stepan [7]
3 years ago
6

Segment HK is divided by point J at a ratio of 3.4. If H(6,9) and J(12, 18), what are the coordinates of point K?

Mathematics
1 answer:
RSB [31]3 years ago
8 0

Answer:

Step-by-step explanation:

x=\frac{mx2+nx1}{m+n}\\let~coordinates ~of~K~be~(x,y)\\12=\frac{3x+4*6}{3+4}\\12*7=3x+24\\3x=84-24\\3x=60\\x=60/3=20\\18=\frac{3y+4*9}{3+4}\\18*7=3y+36\\3y=126-36\\3y=90\\y=90/3=30\\so~K~is~(20,30)

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If f(x)=1/6x+12, then f^-1(x)=<br> PLEASE HELP
Finger [1]

f(x)=\dfrac{1}{6}x+12\to y=\dfrac{1}{6}x+12


Change x to y, and y to x.


x=\dfrac{1}{6}y+12


solve for y:


\dfrac{1}{6}y+12=x\ \ \ |-12\\\\\dfrac{1}{6}y=x-12\ \ \ \ |\cdot6\\\\y=6x-72


Your answer is:


f^{-1}(x)=6x-72

5 0
2 years ago
6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
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404 cm³ Anyway... Look down here for my explanation.

Step-by-step explanation:

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1 year ago
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Answer:

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