Answer:
The answer to your question is: ![\sqrt[4]{2^{3} } + 1](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%5E%7B3%7D%20%7D%20%2B%201)
Step-by-step explanation:
![\frac{1}{\sqrt[4]{2- 1}} x \frac{\sqrt[4]{2^{3}}+ 1 }{\sqrt[4]{2^{3}} + 1} = [tex]\frac{\sqrt[4]{2^{3}}+ 1 }{2 - 1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7B2-%201%7D%7D%20%20x%20%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%20%2B%201%7D%20%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%3D%20%5Btex%5D%5Cfrac%7B%5Csqrt%5B4%5D%7B2%5E%7B3%7D%7D%2B%201%20%7D%7B2%20-%201%7D)
=
Answer:
a. (-3, 2).
b. √65
c. (x + 3)^2 + (y - 2)^2 = 65
Step-by-step explanation:
a. The center is the midpoint of the diameter PQ.
= (-10+4)/2, (-2+6)/2
= (-3, 2).
b. The radius is the distance from the center to a point on the circle.
Take the point (4, 6):
The radius = √((-3-4)^2 + (2-6)^2)
= √65.
c. The equation of the circle is:
Using the standard form
(x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center and r = the radius:
it is (x - (-3)^2 + (y - 2) = 65
= (x + 3)^2 + (y - 2)^2 = 65.
B I’m pretty sure sorry if wrong
<span>You did not include the equations that you want to assess whether they can be used to solve for the radius (r).
Likely, the equation of the circumference, C = 2*Pi*r is included, if so => r = C / (2*Pi).
If you round Pi to 3.14, the equation may be written r = C / 6.28.</span>
Answer:
I don't
Step-by-step explanation:
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