Question

Question 1 options:

Answer 1

Answer:

$\frac{-1+/-3\sqrt{2} }{2}$  where a = 1, b = 1,and c=-4

Step-by-step explanation:

To solve, use the quadratic formula. Using the quadratic formula, requires the standard form $ax^2+bx+c$ Here a = 1, b = 1, and c = -4.

The quadratic formula is $x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$.

Substitute and you'll have:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-1+/-\sqrt{1^2-4(1)(-4)} }{2(1)}=\frac{-1+/-\sqrt{1+17} }{2)}$

$\frac{-1+/-\sqrt{18} }{2}=\frac{-1+/-3\sqrt{2} }{2}$