Ask question

Ask question

All categories

3 years ago

12

Maureen, Frank, Tashia, Zane, Eric, and Wesley are addressing envelopes for volunteer work at a local charity. They were given ¾

of an entire mailing to address to be evenly divided among six of them. What fraction of the entire mailing does each person address?

1 answer:

jolli1 [7]3 years ago

6 0

Answer:

The fraction of the entire mail each person address = 1/8

Step-by-step explanation:

Given that:

number of people addressing envelopes = 6

If they gave out 3/4 of an entire mailing address.

Then, the amount of mailing not addressed is:

= 1 - 3/4

= $\dfrac{4-3}{4}$

= 1/4

If 6 people shared 3/4 of an entire mailing to address evenly.

Then: each person gets:

$=\dfrac{3}{4} \div 6$

$=\dfrac{3}{4} \times \dfrac{1}{ 6}$

= 1/8

The fraction of the entire mail each person address = 1/8

You might be interested in

MULTIPLE CHOICE QUESTION A car travels 120 miles in 2 hours. It goes an average of South East direction. What is its velocity? 6

Ainat [17]

Answer:

60 miles per hour southeast.

Step-by-step explanation:

We are told that the car is moving southeasternly, so that answers the question right off the bat. The car is moving 120 miles per 2 hours. We need to know how much it moves in one hour though, so we must divide hours and miles by 2. We ger 60 miles per hour.

3 0

3 years ago

If y = 7x – 5, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?

Setler79 [48]

The third set, (0, -5) (2,9) (-3,-26)

3 0

3 years ago

Read 2 more answers

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

A ferry departs from a port along the Sands River at 10:00 am. The ferry travels at a speed of 15 mph in still water and returns

jek_recluse [69]

Answer:

Speed of river's current = 5 mph

Step-by-step explanation:

Let 'd' be the distance covered

Let x be the speed of the rivers current

Speed upstream = 15-x

speed downstream = 15+x

Time = distance / speed

time upstream = $\frac{d}{15-x}$

time downstream = $\frac{d}{15+x}$

the ferry trip upstream takes twice as long as its return trip downstream

$\frac{d}{15-x}$ = $\frac{2d}{15+x}$

divide both sides by d

$\frac{1}{15-x}$ = $\frac{2}{15+x}$

cross multiply

$15+x= 2(15-x)$

$15+x= 30-2x$

Add 2x on both sideds

$15+3x= 30$

subtract 15 from both sides and divide by 3

$3x=15$

x=5

Speed of river's current = 5 mph

8 0

3 years ago

How many tens are in 1,000

victus00 [196]

There are 100 tens in 1,000

5 0

3 years ago