1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Margaret [11]
3 years ago
12

Maureen, Frank, Tashia, Zane, Eric, and Wesley are addressing envelopes for volunteer work at a local charity. They were given ¾

of an entire mailing to address to be evenly divided among six of them. What fraction of the entire mailing does each person address?
Mathematics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

The fraction of the entire mail each person address = 1/8

Step-by-step explanation:

Given that:

number of people addressing envelopes = 6

If they gave out 3/4 of an entire mailing address.

Then, the amount of mailing not addressed is:

= 1 - 3/4

= \dfrac{4-3}{4}

= 1/4

If 6 people shared 3/4 of an entire mailing to address evenly.

Then: each person gets:

=\dfrac{3}{4} \div 6

=\dfrac{3}{4} \times \dfrac{1}{ 6}

= 1/8

The fraction of the entire mail each person address = 1/8

You might be interested in
Give two different meanings for each of the phrases below. Use a dictionary to look up the meanings of individual words in each
Nata [24]
A cold wave - a series of cold days in terms of weather; a physical wave that is given by someone with a "cold" demeanor.

A fair day- a day with nice, mild weather; making a modest amount of money in a days work.

hope those help.
8 0
3 years ago
Find the radius of the sphere with a volume of 32/81π cubic yards. Write your answer as a fraction in simplest form. PLEASE HELP
NeTakaya
Area of a sphere = 4(pi)(r)^2
Reverse the equation to find the radius (r)
The answer will be in pi form

32/81(pi)

8/20.25(pi)

Square root of 8/20.25(pi) = radius

r =  2.8(rounded)/4.5(pi)

:)

8 0
3 years ago
What is the inverse of y=2x squared -4
Bumek [7]
y=2x^2-4\ \ \ |+4\\\\2x^2=y+4\ \ \ |:2\\\\x^2=\dfrac{y+4}{2}\\\\x=\sqrt{\dfrac{y+4}{2}}

y^{-1}=\sqrt{\dfrac{x+4}{2}}=\dfrac{\sqrt{x+4}}{\sqrt2}=\dfrac{\sqrt{2(x+4)}}{2}=\dfrac{\sqrt{2x+8}}{2}
6 0
3 years ago
There are 3/4 as many boys as girls in a class of 5th graders if there are 35 students in the class how many are girls?
ziro4ka [17]
Writing an equation is the easiest way to figure this out.
b = boys, g = girlsb = 3/4g35 students = g + b35 = g + 3/4g35 = 7/4g35/7/4 = g20 girls35 - 20 = b or 3/4(35) = b15 boys
3 0
3 years ago
There is a Saturday performance at a local theater. A theater charges $9 for an adult ticket and $4 for a child ticket. All 1020
Whitepunk [10]
Let x tickets sold be adults, then (1024-x) were of childrens tickets, 9x+(1024-x)4 = 7680. The above equation is for total money solve it you will get x=720 hence, number of adult tickets were 720 and number of child tickets were 300 :)
5 0
3 years ago
Read 2 more answers
Other questions:
  • Wiley is making monthly payments of $88.00 to pay off a loan that he took out to buy a fence, but he wants to pay off his loan f
    7·2 answers
  • If the measure of ZFGH is 64º and the measure of ZEGD is (4x+8)°, what is the value of x ?
    13·1 answer
  • . Tell whether the slope of a line that models the linear relationship is positive,
    14·2 answers
  • Need help combing like terms
    12·1 answer
  • 02.06)If 1 pint is equal to 2 cups, then 5 pints would equal ___ cups.
    12·1 answer
  • Suppose y varies directly with x and y=12 when x=-3 what is the value of y when x=6?
    7·1 answer
  • Allyson can pay for her gym membership on a monthly​ basis, but if she pays for an entire​ year's membership in​ advance, she'll
    8·1 answer
  • 5) Write the 5 number summary and draw a box and whisker plot.<br> 58, 67, 44, 72,51, 42, 60, 46, 69
    8·1 answer
  • Consider the following functions
    8·1 answer
  • Question 4 of 5<br> Solve y3 = 125.<br> O A. y = 15<br> O B. y = 25<br> O C. y = 5<br> O D. y = 11.2
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!