When two events are mutually exclusive, why is P(A and B) 0? Explain.

Mathematics

1 answer:

Oliga [24]3 years ago

8 0

probably because they dont happen at the same time so you cant't happen at the same time/.

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PLEAASSEEE HELP ASAP!!!

eduard

Answer:

$= 2 \frac{7}{23} \\ \\$

Step-by-step explanation:

$5 \frac{3}{8} - 3 \frac{1}{6} \\ \\ \frac{43}{8} - \frac{19}{6} \\ \\ \frac{258 - 152}{48} \\ \\ \frac{106}{48} \\ \\ \frac{53}{23} = \: \: 2 \frac{7}{23}$

8 0

4 years ago

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Solve for x with a degree of 30 & side of 300ft

tankabanditka [31]

Answer:

x = 100√3

Step-by-step explanation:

tan(30º) = x/300

x = 300 tan(30º)

x = 300/√3

x = 100√3

3 0

4 years ago

What is the binomial expansion of (x + 2y)7?

borishaifa [10]

<h2>Thus, the required "option 4)" is correct.</h2>

Step-by-step explanation:

We find,

$(x+2y)^7$

To find, the binomial expansion of of $(x+2y)^7$ = ?

We know that,

$(x+y)^{n} =^nC_0x^n+^nC_1x^{n-1}y+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+...+^nC_ny^n$

∴ $(x+2y)^7$

Here, n = 7, x = x and y = 2y

$(x+2y)^7$ = $^7C_0x^7+^7C_1x^{7-1}(2y)+^7C_2x^{7-2}(2y)^2+^7C_3x^{7-3}(2y)^3+^7C_4x^{7-4}(2y)^4+^7C_5x^{7-5}(2y)^5+^7C_6x(2y)^6+(2y)^7$ $=x^7+7x^{6(2y)+21x^{5}4y^2+35x^{4}8y^3+^35x^{3}16y^4+21x^{2}32y^5+7x64y^6+128y^7$