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marissa [1.9K]
3 years ago
6

2.085x10^6 in standard form

Mathematics
1 answer:
wariber [46]3 years ago
7 0

the answer to the problem is 208500000


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Each bus for Philips Elementary School transports 40 students to school. There are 12 buses that transport students to school ea
8090 [49]

Answer:

480 students are transported to school each day.

Step-by-step explanation:

Since there are 12 buses and each one of them transports 40 students that means that the total amount of students will be equal to...

12 x 40 = 480

7 0
3 years ago
NEED HELP ON THIS PLEASE! Oregon Trail: Percents.
harina [27]

1845-1846

118->148

148-118 = 30 = change

percent

30/118 ≈ 25.4%

1846-1847

148->139

148-139 = 9 = change

percent

9/148 ≈ 6%

1847-1848

139->151

151-139 = 12 = change

percent

12/139 ≈ 8.6%


Hope this helped :)

5 0
3 years ago
Please help me solve this equation and show the work show me how you got the answer
Nesterboy [21]

Answer: k=3

Step-by-step explanation:

To solve for k, you want to isolate k.

\frac{2}{5} (5k+35)-8=12            [add both sides by 8]

\frac{2}{5} (5k+35)=20                  [multiply both sides by 5/2]

5k+35=50                       [subtract both sides by 35]

5k=15                               [divide both sides by 5]

k=3

Now, we know that k=3.

7 0
3 years ago
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
Park visitors
Lapatulllka [165]

Answer:

The answer is 225

Step-by-step explanation:

Because you first need to subtract 350-125 and you get 225

3 0
3 years ago
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