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3 years ago

8

Hey I have a link to the question since its kinda complicated

2 answers:

Natalija [7]3 years ago

8 0

Anyway

so the recursive rule tells the relationship between the previous term and the term we want to find

given

an=2n+11
it is clear that the first term is 13
2nd term is 15
3rd term is 17

each term increases by 2
so
a term is equal to the previous term plus 2
an=a(n-1)+2

the first one is the answer

Wewaii [24]3 years ago

3 0

The first one is most likely the answer

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What is the probability of drawing a black ace followed by a heart out

Verdich [7]

Correct option C) 0.98%

<u>Step-by-step explanation:</u>

We know that , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out of a deck when the cards aren't replaced . Let's find out:

Firstly , a black ace is drawn , so probability :

⇒ $P(Black) = \frac{2}{52}$

Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):

⇒ $P(Heart) = \frac{13}{51}$

So , Probability of occurring both events is :

⇒ $P(Black)(P(Heart))$

⇒ $\frac{2}{52} (\frac{13}{51} )$

⇒ $0.0098$

Percentage = $0.0098(100) = 0.98$ %

Therefore , Correct option C) 0.98%

7 0

3 years ago

In 2008, the total trade between the United States and Japan was $2.04 x 101^1. The total trade between the U.S. And Australia w

jolli1 [7]

Answer:

6.21 times more

Step-by-step explanation:

Assuming 2.04 x 10^11 was only a typo

you would need to first equal the powers of 10

so 20.4 x 10^10 and 3.28 x 10^10

now that they have the same powers

$\frac{20.4 * 10^{10}}{3.28 * 10^{10}} = \frac{20.4}{3.28} = 6.219512...$

if it's asking for how many times i would approximate it to 6.21 times more

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3 years ago

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MrRissso [65]

Step-by-step explanation:

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2 years ago

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Hitman42 [59]

Answer:

red 420 times

Step-by-step explanation:

The results show red (18) out of ( 18+10+7+19+6)

18 / 60

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7 0

2 years ago

Someone please help me with #28 and #30 I got myself super confused.

bogdanovich [222]

<u><em>Question 28:</em></u>

$S-2\pi r^2=2\pi rh$ Subtract $2\pi r^2$ on both sides

$\frac{S-2\pi r^2}{2\pi r} =h$ Divide $2\pi r$ on both sides

<u><em>*(Answer)*=</em></u> $\frac{S-2\pi r^2}{2\pi r} =h$

<u><em>Question 30:</em></u>

$a*t=v_{1}+v_{0}$ Multiply $t$ on both sides

$a*t+v_{0} =v_{1}$ Subtract $v_{0}$ on both sides

<u><em>*(Answer)*=</em></u> $a*t+v_{0} =v_{1}$

Hope This Helps

BangtanBoyScouts

4 0

3 years ago