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lesantik [10]
3 years ago
7

Multiply: (sqrt10 +2 sqrt8)(sqrt10-2 sqrt8)

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

(√10 +2√8)(√10 -2√8)=

(10 -8√5 + 8√5 -32)

10+0-32

10-32

= -22

Hope this helps.

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belka [17]

Answer:

10 i think

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,ax
Ivan

Given:

The function is:

f(x)=-2x^2+7x+4

To find:

Express the quadratic equation in the form of f(x)=a(x-h)^2+k, then state the minimum or maximum value,axis of symmetry and minimum or maximum point.

Solution:

The vertex form of a quadratic function is:

f(x)=a(x-h)^2+k              ...(i)

Where, a is a constant, (h,k) is the vertex and x=h is the axis of symmetry.

We have,

f(x)=-2x^2+7x+4

It can be written as:

f(x)=-2\left(x^2-3.5x\right)+4

Adding and subtracting square of half of coefficient of x inside the parenthesis, we get

f(x)=-2\left(x^2-3.5x+(\dfrac{3.5}{2})^2-(\dfrac{3.5}{2})^2\right)+4

f(x)=-2\left(x^2-3.5x+(1.75)^2\right)-2\left(-(1.75)^2\right)+4

f(x)=-2\left(x-1.75\right)^2+2(3.0625)+4

f(x)=-2\left(x-1.75\right)^2+6.125+4

f(x)=-2\left(x-1.75\right)^2+10.125                ...(ii)

On comparing (i) and (ii), we get

a=-2,h=1.75,k=10.125

Here, a is negative, the given function represents a downward parabola and its vertex is the point of maxima.

Maximum value = 10.125

Axis of symmetry : x=1.75

Maximum point = (1.75,10.125)

Therefore, the vertex form of the given function is f(x)=-2\left(x-1.75\right)^2+10.125, the maximum value is 10.125, the axis of symmetry is x=1.75 and the maximum point is (1.75,10.125).

8 0
3 years ago
Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
3 years ago
Which expression has a value that is equivalent to 5n + 13 when n=−5 ?
Orlov [11]
5(-5)+13=-25+13=-12
the answer would be 4n+8
hope this helps!
8 0
3 years ago
Read 2 more answers
102/159 = x/4<br><br> Find X
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102/159 = x/4
34/53 = x/4
34(4) = x(53)
136 = 53x
136/53 = x
5 0
3 years ago
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