3 years ago

What happens when you celebrate halloween in the spring

1 answer:

4 0

Answer:

the day that immediately proceeds the last and final spring sabbat, ... The fact that Beltane and Samhain happen in unison twice a year lends

Step-by-step explanation:

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Which of the following statements is true? A. A tangent is never a secant. B. A secant is always a chord. C. A chord is always a

kvasek [131]

The answer to this is B.

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4 years ago

Evaluate 21/a+4 when a=3

DochEvi [55]

Answer:

Step-by-step explanation:

All you have to do is plug in a. In this case, a=3.

21/a+4

21/(3)+4

21/3+4

7+4

If this helps please mark as brainliest

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3 years ago

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-11=-7/y<br><br> PLSSSS HELPPP

Liono4ka [1.6K]

Answer:

7/11

Step-by-step explanation:

$- 11 = \frac{ - 7}{y}$

$= > - 11y = - 7$

$= > y = \frac{ - 7}{ - 11}$

$= > y = \frac{7}{11} (ans)$

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3 years ago

Write the equation of a line in slope-intercept form. (Brainliest)

Julli [10]

The equation of the line is y=x-2

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3 years ago

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Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx

ikadub [295]

Answer:

<em>Explicación más abajo</em>

Step-by-step explanation:

Integración Indefinida

La integral

$I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}$

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

$I=sen(t)-t.cos(t)+C$

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

$cos(t)=\sqrt{1-sen^2(t)}$

Entonces:

$cos(t)=\sqrt{1-x^2}$

Devolviendo los cambios:

$I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C$

Es la respuesta correcta

7 0

3 years ago