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Grace [21]
3 years ago
11

Find the arc length of the partial circle.

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Answer:

11

Step-by-step explanation:

=  \frac{1}{2} \pi \: r \\  =  \frac{1}{2}  \times  \frac{22}{7}  \times 7 \\  =  \frac{1}{2}  \times 22 \\  = 11

Maru [420]3 years ago
4 0

Answer:

11

Step-by-step explanation:

\frac{90}{360}  \times 2 \times \pi \times 7 \\  \frac{1}{4}  \times 2 \times  \frac{22}{7}  \times 7 \\  = 11

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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
3 years ago
Can someone please answer this?
telo118 [61]
Yes i can answer this
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3 years ago
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Step-by-step explanation:

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Oxana [17]
ANSWER:
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6 0
3 years ago
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