Question

a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface are negative,which expression represents one way to calculate the location of the diver after 12 1/2 seconds?

Answer 1

Answer:

The location will be at $- 28\frac{1}{8}$ units.

Step-by-step explanation:

A scuba diver descended at a rate of $2\frac{1}{4}$ units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after $12\frac{1}{2}$ seconds the location of the diver will be given by the followings :

In one second the diver descends by 2.25 units depth.

So, in 12.5 seconds the diver will descend by $(2.25 \times 12.5) = 28.125$ units i.e. $28\frac{1}{8}$ units depth.

Therefore, the location will be at $- 28\frac{1}{8}$ units. (Answer)