In an isolated environment, a disease spreads at a rate proportional to the product of the infected and non-infected populations
. Let I(t) denote the number of infected individuals. Suppose that the total population is 2000, the proportionality constant is 0.0001, and that 1% of the population is infected at time t-0, write down the intial value problem and the solution I(t). dI/dt =
1(0) =
I(t) =
symbolic formatting help
Favor out a-1 as long as you do it to the whole problem it is now equivalent then just worry about factoring the new product -1(8x^2+X-9) (8x+9)((X-1) 8x+9=0 Subtract 9 divide by 8 X=-9/ 8 answer X-1=0 X=1 answer