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2 years ago

I need big help 10 points whoever answers

Mathematics

1 answer:

denpristay [2]2 years ago

7 0

Answer:

The answer to this question is not 36/25 but 6 1/10.

Step-by-step explanation:

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Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

To know more visit:

brainly.com/question/3023490

8 0

2 years ago

in a certain year a new bed costs 35000. if the rate of inflation was 20% for the next two years what would the same bed cost at

Neko [114]

Answer:

42000

Step-by-step explanation:

First of all, we need to find 20 percent of 35000.

35000×20 / 100 = 7000

now we increase the bed cost by 20 percent.

35000 + 7000 = 42000

7 0

3 years ago

Read 2 more answers

The point (-2, -1) satisfies which of the following inequalities?

satela [25.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s

nignag [31]

Answer:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

Step-by-step explanation:

Given

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Required

Solve

We have:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Collect like terms

$1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t + 8$

$1.3t^3 + t^2 -42t + 8$

So:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

8 0

2 years ago

Helppppp please please please

Firlakuza [10]

Answer:

its d

Step-by-step explanation:

used photo math

4 0

1 year ago

Read 2 more answers