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sveticcg [70]
2 years ago
5

I need big help 10 points whoever answers

Mathematics
1 answer:
denpristay [2]2 years ago
7 0

Answer:

The answer to this question is not 36/25 but 6 1/10.

Step-by-step explanation:

You might be interested in
Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows
Paul [167]

The value of cement mixer after t year is f(t) = 54,205(0. 87)^{t}

Given to us

The value of cement mixer when bought, P= $ 54,205

the value of cement mixer after 1 year, P_1=   $ 47,158. 35

the value of cement mixer after 2 year,P_2=  $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years

By putting the value, in the formula we get,

P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13

Therefore, putting the value of r and P in depreciation formula for t years we get,

P_n= P(1-r)^n

f(t) = 54,205(0. 87)^{t}

Hence, the value of cement mixer after t year is f(t) = 54,205(0. 87)^{t}.

To know more visit:

brainly.com/question/3023490

8 0
2 years ago
in a certain year a new bed costs 35000. if the rate of inflation was 20% for the next two years what would the same bed cost at
Neko [114]

Answer:

42000

Step-by-step explanation:

First of all, we need to find 20 percent of 35000.

35000×20 / 100 = 7000

now we increase the bed cost by 20 percent.

35000 + 7000 = 42000

7 0
3 years ago
Read 2 more answers
The point (-2, -1) satisfies which of the following inequalities?
satela [25.4K]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s
nignag [31]

Answer:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

Step-by-step explanation:

Given

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Required

Solve

We have:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)

Collect like terms

1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t  + 8

1.3t^3 + t^2 -42t  + 8

So:

(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t  + 8

8 0
2 years ago
Helppppp please please please
Firlakuza [10]

Answer:

its d

Step-by-step explanation:

used photo math

4 0
1 year ago
Read 2 more answers
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